0 0 votes For a chemical reaction, the ratio of rate constant at $500\:K$ to that at $400\:K$ is $2.5$. Given $R=8.314\:J$ mol$^{-1}$ $K^{-1}$, the value of activation energy (in $kJ$/mol) is $10.5$ $12.0$ $15.2$ $18.4$ Chemical Reaction Engineering gate2018 chemical-reaction-engineering process-calculations-and-thermodynamics numerical-answers + – gatecse 3.4k points answer Follow 0 reply