A leaf filter is operated at $1$ atm (gauge). The volume of filtrate collected $\left(V\right.$ in $\left.\mathrm{m}^{3}\right)$ is related with the volumetric flow rate of the filtrate $\left(q\right.$ in $\left.\mathrm{m}^{3} / \mathrm{s}\right)$ as:
$$ \frac{1}{q}=\frac{1}{d V / d t}=50 V+100 $$
The volumetric flow rate of the filtrate at $1$ hour is $\_\_\_\_\_\_$ $\times 10^{-3} \mathrm{~m}^{3} / \mathrm{s}$ (rounded off to $2$ decimal places).
