At a shear rate of $10\:s^{-1}$, the apparent viscosity of a non-Newtonian liquid was found to be $1\: Pa\:s$. At a shear rate of $100\:s^{-1}$, the apparent viscosity of the same liquid was found to be $0.5\:Pa\:s$. If the liquid follows power law behavior, the apparent viscosity (in $Pa\:s$) at a shear stress of $10\:N\:m^{-2}$ is ______________ (rounded off two decimal place).