in Others edited by
0 votes
0 votes
The reversible reaction of $t$-butyl alcohol $(TBA)$ and ethanol $(EtOH)$ to ethyl $t$-butyl ether $(ETBE)$ is

$$TBA+Et0H\rightleftharpoons ETBE+water$$

The equilibrium constant for this reaction is $K_{C}=1$. Initially, $74\:g$ of $TBA$ is mixed with $100\:g$ of aqueous solution containing $46$ weight$\%$ ethanol. The molecular weights are: $74\:g$/mol for $TBA$, $46\:g$/mol for $EtOH$, $102\:g$/mol for $ETBE$, and $18\:g$/mol for water.

The amss of $ETBE$ at equilibrium, rounded to $1$ decimal, place, is _______________ $g$.
in Others edited by
7.9k points

Please log in or register to answer this question.

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
Welcome to GATE Chemical Q&A, where you can ask questions and receive answers from other members of the community.