Cyclohexane $\left(\mathrm{C}_{6} \mathrm{H}_{12}\right)$ is produced from benzene $\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ and hydrogen $\left(\mathrm{H}_{2}\right)$ according to the following reaction.
\[
\mathrm{C}_{6} \mathrm{H}_{6}+3 \mathrm{H}_{2} \rightarrow \mathrm{C}_{6} \mathrm{H}_{12}
\]
Consider the process flow diagram shown in the figure.
In this process, the overall and single-pass conversions are $90 \%$ and $25 \%$, respectively. The recycle stream contains $25 \mathrm{~mol} \% \mathrm{~C}_{6} \mathrm{H}_{6}$ and $75 \mathrm{~mol} ~\% \mathrm{~H}_{2}$. If the fresh feed contains $25 \%$ excess $\mathrm{H}_{2}$, at steady state, the ratio of the molar flow rate of recycle stream to that of the fresh feed is $\_\_\_\_$ (rounded off to one decimal place).
