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Consider the normal probability distribution function
\[
f(x)=\frac{4}{\sqrt{2 \pi}} e^{-8(x+3)^{2}}
\]

If $\mu$ and $\sigma$ are the mean and standard deviation of $f(x)$ respectively, then the ordered pair $(\mu, \sigma)$ is

  1. $\left(3, \frac{1}{4}\right)$
  2. $\left(-3, \frac{1}{4}\right)$
  3. $(3,4)$
  4. $(-3,4)$

1 Answer

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Probability density function:

f(x) = (1/σ√2∏)e^-((x-µ)^2/(2σ^2)
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