1 1 vote The first non-zero term in the Taylor series expansion of $(1-x)-e^{-x}$ about $x=0$ is$1$$-1$$\frac{x^{2}}{2}$$-\frac{x^{2}}{2}$ Calculus gatech-2024 calculus taylor-series + – admin 3.5k points answer Follow 0 reply
