0 votes 0 votes The first non-zero term in the Taylor series expansion of $(1-x)-e^{-x}$ about $x=0$ is$1$$-1$$\frac{x^{2}}{2}$$-\frac{x^{2}}{2}$ Others gatech-2024 + – admin asked Feb 16 • edited Mar 13 by makhdoom ghaya admin 2.8k points answer See all 0 reply