Six persons $\text{P, Q, R, S, T and U}$ are sitting around a circular table facing the center not necessarily in the same order. Consider the following statements:

• $P$ sits next to $S$ and $T$.
• $Q$ sits diametrically opposite to $P$.
• The shortest distance between $S$ and $R$ is equal to the shortest distance between $T$ and $U$.

Based on the above statements, $Q$ is a neighbor of

1. $U$ and $S$
2. $R$ and $T$
3. $R$ and $U$
4. $P$ and $S$

Given that, six persons $\text{P, Q, R, S, T}$ and $\text{U}$ are sitting around a circular table facing the center not necessarily in the same order.

• $\text{P}$ sits next to $\text{S}$ and $\text{T}$.
• $\text{Q}$ sits diametrically opposite to $\text{P}$.
• The shortest distance between $\text{S}$ and $\text{R}$ is equal to the shortest distance between $\text{T}$ and $\text{U}$.

Based on the above statements, we can draw the sitting arrangements.

We can also draw the diagram, by changing the position of $\text{S, T}$ and $\text{R, U},$ because there is no restriction for these persons.

Based on the above two diagrams, $\text{Q}$ is a neighbor of $\text{R and U}.$

Correct Answer $:\text{C}$

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