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If $i = \sqrt{-1}$, the value of the integral

                                                        $$\oint_{c}\dfrac{7z + i}{z(z^2 + 1)}dz \quad\quad\quad\quad|z|<2$$,

using the cauchy residue theorem is

  1. $2\pi i$
  2. $0$
  3. $-6\pi$
  4. $6\pi$

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