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GATE Chemical 2012 | Question: 3
Milicevic3306
asked
in
Calculus
Mar 25, 2018
edited
Mar 15, 2021
by
soujanyareddy13
0
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0
votes
For the function $f(t) = e^{-t}/\tau$,
the Taylor series approximation for $t\ll$$\tau$ is
$1+\frac{t}{\tau}$
$1-\frac{t}{\tau}$
$1-\frac{t^2}{2\tau^2}$
$1+t$
gate2012
calculus
taylor-series
Milicevic3306
asked
in
Calculus
Mar 25, 2018
edited
Mar 15, 2021
by
soujanyareddy13
by
Milicevic3306
7.9k
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