$we get $(4-\lambda)(4-\lambda)-9 \Rightarrow \lambda^2-8\lambda-9$
$\lambda^2-8\lambda-\lambda+7\Rightarrow \lambda(\lambda-7)-1(\lambda-7)$
$\lambda-7$ and $ \lambda-1 $are factors of the equation,
we need to find the eigen vectors for the following eigen values
and for 7 we get the given EV
4-7=-3 3
3 4-7=-3
to get zero vector we need vector(1,1) for eigen value 7.