Given No. of Mathematics Students = 10
No. of English students = 12
No. of both Mathematics and English = 4
No. of neither Mathematics nor English = 6
No . of Studnet who likes atleast Math and English n(M U E ) = N(M ) + n(E) - n(N intersection E)
10 + 12 - 4 = 22 - 4 = 18
Total number of studnet in Group = 18 + 6 = 24
So option C is correct .
