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An equation of state is explicit in pressure $p$ and cubic in the specific volume $v$. At the critical point $ā€˜c’$ , the isotherm passing through $ā€˜c’$ satisfies

  1. $\frac{\partial p}{\partial v} < 0, \frac{\partial^2 p}{\partial v^2} = 0$
  2. $\frac{\partial p}{\partial v} > 0, \frac{\partial^2 p}{\partial v^2} > 0$
  3. $\frac{\partial p}{\partial v} = 0, \frac{\partial^2 p}{\partial v^2} > 0$
  4. $\frac{\partial p}{\partial v} = 0, \frac{\partial^2 p}{\partial v^2} = 0$
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