0 0 votes Let $A$ be a square matrix of size $n \times n (n>1)$. The elements of $A=\{a_{ij}\}$ are given by $$a_{ij} = \begin{cases} i \times j, & \text{if } i \geq j \\ 0, & \text{if } i < j \end{cases}$$ The determinant of $A$ is $0$ $1$ $n!$ $(n!)^2$ Linear Algebra gatech-2021 linear-algebra matrix-algebra determinant + – go_editor 1.4k points answer Follow 0 reply
