Match the reaction in $\textbf{Group – 1}$ with the reaction type in $\textbf{Group – 2}$.
$\begin{array}{|c|l|c|l|} \hline & \textbf{Group – 1} && \textbf{Group – 2} \\ \hline P & \text{Methylcyclohexane} \rightarrow \text{Toluene} + 3H_2 & \text{I} . & \text{Dehydrocyclization} \\ \hline Q & \text{Ethylecyclopentane}\rightarrow \text{Methylcyclohexane} & \text{II} & \text{Cracking} \\ \hline R & n-\text{Octane} \rightarrow \text{Ethylbenzene} +4H_2 & \text{III}& \text{Dehydrogenetaion} \\ \hline S & n- \text{Octane} \rightarrow n-\text{Pentane} + \text{Propylene} & \text{IV} & \text{Isomerization} \\ \hline \end{array}$
The correct combination is
- $\text{P-II, Q-III, R-I, S-IV}$
- $\text{P-III, Q-IV, R-I, S-II}$
- $\text{P-III, Q-IV, R-II, S-I}$
- $\text{P-I, Q-IV, R-III, S-II}$