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In a box, there are $5$ green balls and $10$ blue balls. A person picks $6$ balls randomly. The probability that the person has picked $4$ green balls and $2$ blue balls is

  1. $\dfrac{42}{1001}\\$
  2. $\dfrac{45}{1001}\\$
  3. $\dfrac{240}{1001} \\$
  4. $\dfrac{420}{1001}$
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