0 votes 0 votes The Laplace transform of a function is $\frac{s+1}{s\left ( s+2 \right )}$ The initial and final values, respectively, of the function are $0$ and $1$ $1$ and $\frac{1}{2}$ $\frac{1}{2}$ and $1$ $\frac{1}{2}$ and $0$ Differential equations gate2017 differential-equations laplace-transforms + – Milicevic3306 asked Mar 26, 2018 recategorized Mar 14, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer See all 0 reply