The reversible reaction of $t$-butyl alcohol $(TBA)$ and ethanol $(EtOH)$ to ethyl $t$-butyl ether $(ETBE)$ is
$$TBA+Et0H\rightleftharpoons ETBE+water$$
The equilibrium constant for this reaction is $K_{C}=1$. Initially, $74\:g$ of $TBA$ is mixed with $100\:g$ of aqueous solution containing $46$ weight$\%$ ethanol. The molecular weights are: $74\:g$/mol for $TBA$, $46\:g$/mol for $EtOH$, $102\:g$/mol for $ETBE$, and $18\:g$/mol for water.
The amss of $ETBE$ at equilibrium, rounded to $1$ decimal, place, is _______________ $g$.