edited by
0 votes
0 votes

A person is drowning in sea at location $R$ and the lifeguard is standing at location $P$. The beach boundary is straight and horizontal, as shown in the figure.

The lifeguard runs at a speed of $V_{L}$ and swims at a speed of $V_{s}$. In order to reach to the drowning person in optimum time , the lifeguard should choose point $Q$ such that 

  1. $\frac{sin^{2}\Theta _{L}}{sin^{2}\Theta _{S}}=\frac{V_{S}}{V_{L}}$
  2. $\frac{sin\Theta _{L}}{sin\Theta _{S}}=\frac{V_{S}}{V_{L}}$
  3. $\frac{sin^{2}\Theta _{L}}{sin^{2}\Theta _{S}}=\frac{V_{L}}{V_{S}}$
  4. $\frac{sin\Theta _{L}}{sin\Theta _{S}}=\frac{V_{L}}{V_{S}}$
edited by

Please log in or register to answer this question.

Answer: