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Operators $\square$ , $\lozenge$ and ${\rightarrow}$ are defined by: $a\:\square \:b=\frac{a-b}{a+b}; \:a\:\lozenge \:b=\frac{a+b}{a-b};\:a\rightarrow b=ab.$ 

Find the value of  $\left ( 66\:\square \:6 \right )\rightarrow \left ( 66\:\lozenge \:6\right ).$

  1. $-2$
  2. $-1$
  3. $1$
  4. $2$


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