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The solution of the differential equation

$\frac{d^2y}{dx^2}$ – $\frac{dy}{dx}$ + 0.25y = 0, given y = 0 at x = 0 and  $\frac{dy}{dx}$ = 1 at x = 0 is

  1. xe$^{0.5x}$ – xe$^{-0.5x}$
  2. 0.5xe$^{x}$ – 0.5xe$^{-x}$
  3. xe$^{0.5x}$
  4. -xe$^{0.5x}$
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