0 votes 0 votes Which one of the following is the CORRECT value of $y,$ as defined by the expression given below? $$y=\lim _{x \rightarrow 0} \frac{2 x}{e^x-1}$$ $1$ $2$ $0$ $\infty$ Others gatech-2023 + – admin asked May 21, 2023 • edited Nov 28, 2023 by makhdoom ghaya admin 2.8k points answer See all 0 reply
0 votes 0 votes First apply limit & check (0/0) Then apply L’Hospital Rule differentiate numerator & denominator seperately function will be 2/$e^x$ apply given limit on new above function = 2 (Ans. will be B) Shubham CHE answered Aug 28, 2023 Shubham CHE 180 points comment Share ask related question See all 0 reply Please log in or register to add a comment.