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Which one of the following is the CORRECT value of $y,$ as defined by the expression given below? 

$$y=\lim _{x \rightarrow 0} \frac{2 x}{e^x-1}$$

  1. $1$
  2. $2$
  3. $0$
  4. $\infty$ 
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First apply limit & check (0/0)

Then apply L’Hospital Rule differentiate numerator & denominator seperately

 function will be 2/$e^x$

apply given  limit on new above function = 2 (Ans. will be B)
Answer: